3025. Find the Number of Ways to Place People I: Challenge: Medium
This question asks to count the number of ways to arrange points in a 2D array (array of integers representing coordinates) such that no other points are within a specified rectangle area (including its borders). The points can be placed in any order, but the arrangement must be valid according to the given conditions:- Points A and B must be on the upper left of points C and D.
- There must be at least one point within the rectangle (excluding the border).
- The rectangle has a fixed size of 2x2, with the upper left corner at (1, 1) and the lower right corner at (3, 3).
The function numberOfPairs
takes an array of coordinates as input and returns the count of valid arrangements.
Here’s a step-by-step approach to solve this problem in PHP:
1. Initialize a counter $count
to 0.
2. Iterate through each row of the input array:
– For each point $i
in the row, iterate through each
3025. Find the Number of Ways to Place People I
Difficulty: Medium
Topics: Array
, Math
, Geometry
, Sorting
, Enumeration
, Biweekly Contest 123
You are given a 2D array points
of size n x 2
representing integer coordinates of some points on a 2D plane, where points[i] = [xi, yi]
.
Count the number of pairs of points (A, B)
, where
-
A
is on the upper left side ofB
, and - there are no other points in the rectangle (or line) they make (including the border).
Return the count.
Example 1:
- Input: points = [[1,1],[2,2],[3,3]]
- Output: 0
-
Explanation:
- There is no way to choose
A
andB
soA
is on the upper left side ofB
.
- There is no way to choose
Example 2:
- Input: points = [[6,2],[4,4],[2,6]]
- Output: 2
-
Explanation:
- The left one is the pair
(points[1], points[0])
, wherepoints[1]
is on the upper left side ofpoints[0]
and the rectangle is empty. - The middle one is the pair
(points[2], points[1])
, same as the left one it is a valid pair. - The right one is the pair
(points[2], points[0])
, wherepoints[2]
is on the upper left side ofpoints[0]
, butpoints[1]
is inside the rectangle so it’s not a valid pair.
- The left one is the pair
Example 3:
- Input: points = [[3,1],[1,3],[1,1]]
- Output: 2
-
Explanation:
- The left one is the pair
(points[2], points[0])
, wherepoints[2]
is on the upper left side ofpoints[0]
and there are no other points on the line they form. Note that it is a valid state when the two points form a line. - The middle one is the pair
(points[1], points[2])
, it is a valid pair same as the left one. - The right one is the pair
(points[1], points[0])
, it is not a valid pair aspoints[2]
is on the border of the rectangle.
- The left one is the pair
Constraints:
2 <= n <= 50
points[i].length == 2
0 <= points[i][0], points[i][1] <= 50
- All
points[i]
are distinct.
Hint:
- We can enumerate all the upper-left and lower-right corners.
- If the upper-left corner is
(x1, y1)
and lower-right corner is(x2, y2)
, check that there is no point(x, y)
such thatx1 <= x <= x2
andy2 <= y <= y1
.
Solution:
We need to count the number of pairs of points (A, B) such that point A is in the upper left position relative to point B, and there are no other points within the rectangle formed by A and B, including its borders.
Approach
- Check Valid Pairs: For each pair of distinct points (A, B), verify if A is in the upper left position relative to B. This means that the x-coordinate of A must be less than or equal to the x-coordinate of B, and the y-coordinate of A must be greater than or equal to the y-coordinate of B. Additionally, there must be at least one strict inequality to ensure the points are distinct in either the x or y direction.
- Check for Other Points: For each valid pair (A, B), check if there is any other point that lies within or on the borders of the rectangle defined by A and B. The rectangle is defined by x-range [Ax, Bx] and y-range [By, Ay]. If no such point exists, the pair is counted.
- Iterate Through All Pairs: Use nested loops to iterate through all possible pairs of points, and for each pair, check the conditions mentioned above. The solution efficiently checks all pairs and validates them against the constraints.
Let’s implement this solution in PHP: 3025. Find the Number of Ways to Place People I
<?php
/**
* @param Integer[][] $points
* @return Integer
*/
function numberOfPairs($points) {
...
...
...
/**
* go to ./solution.php
*/
}
// Test cases
$points1 = [[1,1],[2,2],[3,3]];
echo numberOfPairs($points1) . PHP_EOL; // 0
$points2 = [[6,2],[4,4],[2,6]];
echo numberOfPairs($points2) . PHP_EOL; // 2
$points3 = [[3,1],[1,3],[1,1]];
echo numberOfPairs($points3) . PHP_EOL; // 2
?>
Explanation:
-
Initialization: The function starts by initializing a counter
$count
to zero. -
Nested Loops: The outer loops iterate over each point
$i
as point A, and the inner loops iterate over each point$j
as point B. If$i
and$j
are the same, the loop continues to the next iteration. - Check Upper Left Condition: For each pair (A, B), the code checks if A is in the upper left position relative to B by verifying that A’s x-coordinate is less than or equal to B’s x-coordinate, and A’s y-coordinate is greater than or equal to B’s y-coordinate, with at least one strict inequality.
- Check for Other Points: If the pair (A, B) satisfies the upper left condition, the code checks all other points to ensure no point lies within or on the borders of the rectangle defined by A and B. If any such point is found, the pair is invalid.
-
Count Valid Pairs: If no other points are found within the rectangle, the counter
$count
is incremented. - Return Result: After processing all pairs, the function returns the total count of valid pairs.
This approach efficiently checks all possible pairs of points and validates them against the given conditions, ensuring correctness while maintaining clarity. The complexity is O(n3), which is feasible given the constraint that n
is at most 50.
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